Dizzy

Description

By hofill

Embark on 'Dizzy', a carousel ride through cryptography! This warmup challenge spins you around the basics of ciphers and keys. Sharpen your mind, find the flag, and remember - in crypto, it's fun to get a little dizzy!

T4 l16 _36 510 _27 s26 _11 320 414 {6 }39 C2 T0 m28 317 y35 d31 F1 m22 g19 d38 z34 423 l15 329 c12 ;37 19 h13 _30 F5 t7 C3 325 z33 _21 h8 n18 132 k24

Solution

Cipher Identifier by dCode shows that it's highly likely to be Letters Positions.

Decryption returns:

TFCCTF{th_chllng_mks_m_dzzy_;d}

Flag is incomplete.

>>> len("T4 l16 _36 510 _27 s26 _11 320 414 {6 }39 C2 T0 m28 317 y35 d31 F1 m22 g19 d38 z34 423 l15 329 c12 ;37 19 h13 _30 F5 t7 C3 325 z33 _21 h8 n18 132 k24".split())
40
>>> len("TFCCTF{th_chllng_mks_m_dzzy_;d}")
31

Let's try to implement decoder ourselfves:

>>> cipher = 'T4 l16 _36 510 _27 s26 _11 320 414 {6 }39 C2 T0 m28 317 y35 d31 F1 m22 g19 d38 z34 423 l15 329 c12 ;37 19 h13 _30 F5 t7 C3 325 z33 _21 h8 n18 132 k24'.split()
>>> flag = [''] * len(cipher)
>>> flag
['', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '']
>>> for pair in cipher:
...     char, pos = pair[0], int(pair[1:])
...     flag[pos] = char
...
>>> ''.join(flag)
'TFCCTF{th15_ch4ll3ng3_m4k3s_m3_d1zzy_;d}'

Flag: TFCCTF{th15_ch4ll3ng3_m4k3s_m3_d1zzy_;d}